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3x^2-76x+325=0
a = 3; b = -76; c = +325;
Δ = b2-4ac
Δ = -762-4·3·325
Δ = 1876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1876}=\sqrt{4*469}=\sqrt{4}*\sqrt{469}=2\sqrt{469}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-2\sqrt{469}}{2*3}=\frac{76-2\sqrt{469}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+2\sqrt{469}}{2*3}=\frac{76+2\sqrt{469}}{6} $
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